9x^2-16x+52=8x^2

Solution for 9x^2-16x+52=8x^2 equation:

9x^2-16x+52=8x^2

We move all terms to the left:

9x^2-16x+52-(8x^2)=0

determiningTheFunctionDomain
9x^2-8x^2-16x+52=0

We add all the numbers together, and all the variables

x^2-16x+52=0

a = 1; b = -16; c = +52;
Δ = b2-4ac
Δ = -162-4·1·52
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{3}}{2*1}=\frac{16-4\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{3}}{2*1}=\frac{16+4\sqrt{3}}{2}
$